Q. Kaidah Pencacahan :-;

• Permutasi

Total huruf = 9

Unsur ganda = –

9!

= 9×8×7×6×5×4×3×2

= 362.880 susunan

• Kombinasi

K = 1

O = 1

M = 1

B = 1

I = 2

N = 1

A = 1

S = 1

Total huruf = 9

Unsur ganda = 2

9!/2!

= 362.880/2

= 181.440 susunan

• Matematika

M = 2

A = 3

T = 2

E = 1

I = 1

K = 1

Total huruf = 10

Unsur ganda = 3!.2!.2!

10!/3!.2!.2!

= 3.628.800/24

= 151.200 susunan

Penjelasan dengan langkah-langkah:

1)

P = 1

E = 1

R = 1

M = 1

U = 1

T = 1

A = 1

S = 1

I = 1

Jumlah Huruf = 9

= 9!

= 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 15.120 x 24

= 362.880 Susunan

2)

K = 1

O = 1

M = 1

B = 1

I = 2

N = 1

A = 1

S = 1

Jumlah Huruf = 9

= 9!/2!

= 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2!/2!

= 9 x 8 x 7 x 6 x 5 x 4 x 3

= 181.440 Susunan

3)

M = 2

A = 3

T = 2

E = 1

I = 1

K = 1

Jumlah Huruf = 10

= 10!/2!3!2!

= 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3!/2!3!2!

= 10 x 9 x 8 x 7 x 6 x 5 x 4/2 x 1 x 2 x 1

= 604.800/4

= 151.200 Susunan