Q. math~f(x) = 5x² + 19xf”(x) = …​

f(x) = 5x² + 19x

f'(x) = 2 × 5 × x^(2 – 1) + 1 × 19 × x^(1 – 1)

f'(x) = 10x¹ + 19x⁰

f'(x) = 10x + 19

f"(x) = 1 × 10 × x^(1 – 1) + 0

f"(x) = 10x⁰ + 0

f"(x) = 10 + 0

f"(x) = 10

✧Jawaban:

f(x) = 5x² + 19x

f"(x) = 5(2)(2 – 1)x²-² + 19(1)(1 – 1)x¹-¹

f"(x) = 5(2)(1)x⁰ + 19(1)(0)x⁰

f"(x) = 5(2)x⁰ + 19(0)x⁰

f"(x) = 10x⁰ + 0x⁰

f"(x) = 10(1) + 0(1)

f"(x) = 10 + 0

f"(x) = 10