Q. night Spesial

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Lim x³ – 7x + 2x
x → 5
—-

Jika
A = 2²
B = 3³
C = 4⁴
Maka tentukan
• A x B x C x 0
• 0 x B x C ​

Q. night Spesial

Lim = x³ – 7x + 2x

x → 5

= 5³ – 7(5) + 2(5)

= (5 × 5 × 5) – (7 × 5) + (2 × 5)

= 125 – 35 + 10

= 90 + 10

= 100

_________

Diket:

A = 2²

B = 3³

C = 4⁴

Ditanya:

• A x B x C x 0

• 0 x B x C

Jawab:

• 2² × 3³ × 4⁴ × 0 =

= (2.2) × (3.3.3) × (4.4.4.4) × 0

= 4 × 27 × 256 × 0

= 108 × 256 × 0

= 27.648 × 0

= 0

• 0 × 3³ × 4⁴ =

= 0 × (3.3.3) × (4.4.4.4)

= 0 × 27 × 256

= 0 × 256

= 0

Penyelesaian :

Lim x³ – 7x + 2x

x => 5

  • Lim x³ – 7x + 2x
  • Lim 5³ – 7(5) + 2(5)
  • Lim (5 × 5 × 5) – (7 × 5) + (2 × 5)
  • Lim (25 × 5) – 35 + 10
  • Lim 125 – 35 + 10
  • Lim 90 + 10
  • => 100

=================================

Jika

A = 2²

B = 3³

C = 4⁴

Maka tentukan

• A x B x C x 0

• 0 x B x C

  • A = 2² = 2 × 2 = 4
  • B = 3³ = 3 × 3 × 3 = 9 × 3 = 27
  • C = 4⁴ = 4 × 4 × 4 × 4 = 16 × 16 = 256

==================================

A × B × C × 0

4 × 27 × 256 × 0

108 × 256 × 0

27.648 × 0

0

==================================

0 × B × C

0 × 27 × 256

0 × 256

0

==================================