Lim x³ – 7x + 2x
x → 5
—-
Jika
A = 2²
B = 3³
C = 4⁴
Maka tentukan
• A x B x C x 0
• 0 x B x C
Q. night Spesial
Lim = x³ – 7x + 2x
x → 5
= 5³ – 7(5) + 2(5)
= (5 × 5 × 5) – (7 × 5) + (2 × 5)
= 125 – 35 + 10
= 90 + 10
= 100
_________
Diket:
A = 2²
B = 3³
C = 4⁴
Ditanya:
• A x B x C x 0
• 0 x B x C
Jawab:
• 2² × 3³ × 4⁴ × 0 =
= (2.2) × (3.3.3) × (4.4.4.4) × 0
= 4 × 27 × 256 × 0
= 108 × 256 × 0
= 27.648 × 0
= 0
• 0 × 3³ × 4⁴ =
= 0 × (3.3.3) × (4.4.4.4)
= 0 × 27 × 256
= 0 × 256
= 0
Penyelesaian :
Lim x³ – 7x + 2x
x => 5
- Lim x³ – 7x + 2x
- Lim 5³ – 7(5) + 2(5)
- Lim (5 × 5 × 5) – (7 × 5) + (2 × 5)
- Lim (25 × 5) – 35 + 10
- Lim 125 – 35 + 10
- Lim 90 + 10
- => 100
=================================
Jika
A = 2²
B = 3³
C = 4⁴
Maka tentukan
• A x B x C x 0
• 0 x B x C
- A = 2² = 2 × 2 = 4
- B = 3³ = 3 × 3 × 3 = 9 × 3 = 27
- C = 4⁴ = 4 × 4 × 4 × 4 = 16 × 16 = 256
==================================
A × B × C × 0
4 × 27 × 256 × 0
108 × 256 × 0
27.648 × 0
0
==================================
0 × B × C
0 × 27 × 256
0 × 256
0
==================================