Q1. Terlampir2. 7! × 3! ÷ 2! = 3. 5³ + 2xx => 5​

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Q1. Terlampir2. 7! × 3! ÷ 2! = 3. 5³ + 2xx => 5​

Jawaban

1.

sqrt[3]{343} \ = 7 {}^{3} \ = 7 times 7 times 7

2. 7! × 3! ÷ 2!

= (7 × 6 × 5 × 4 × 3 × 2 × 1) × (3 × 2 × 1) ÷ (2 × 1)

= (42 × 5 × 4 × 3 × 2 × 1) × (6 × 1) ÷ 2

= (210 × 4 × 3 × 2 × 1) × 6 ÷ 2

= (840 × 3 × 2 × 1) × 6 ÷ 2

= (2.520 × 2 × 1) × 6 ÷ 2

= (5.040 × 1) × 6 ÷ 2

= 5.040 × 6 ÷ 2

= 30.240 ÷ 2

= 15.120

3. 5³ + 2x

x => 5

5³ + 2(5)

= (5 × 5 × 5) + 10

= (25 × 5) + 10

= 125 + 10

= 135

Jawaban:

1). 7

2). 15.120

3). 135

Penjelasan dengan langkah-langkah:

1). ³√343

= ³√7³

= 7

2). 7! × 3! ÷ 2!

= 7.6.5.4.3.2.1 × 3.2.1 × 2.1

= 5.040 × 3

= 15.120

3). 5³ + 2x

= 5³ + 2(5)

= 125 + 10

= 135