Ques [+50]Soal:Permutasi dari kata “ayumiathifa475″​

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Ques [+50]Soal:Permutasi dari kata “ayumiathifa475″​

Penjelasan dengan langkah-langkah:

ayumiathifa475

a=3

i=2

Jumlah huruf=14

= 14! / 3! × 2!

= 14×13×12×11×10×9×8×7×6×5×4×3×2×1/3×2×1 × 2×1

= 87.178.291.200/12

= 7.264.857.600 susunan kata

• Ayumiathifa457

Jumlah huruf & angka = 14

Huruf / angka ganda =

  • A = 3
  • I = 2

P = n! ÷ k!

P = 14! ÷ 3!.2!

P = 14×13×12×11×10×9×8×7×6×5×4×3×2 / 3×2×2

P = 87.178.291.200 / 12

P = 7.264.857.600 Susunan

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