1. Berapa luas permukaan balok jika panjangnya 10 cm lebar 5 cm dan tinggi 6 cm
2. 5³ + 6²
Quiss
Jawaban:
Lp = 2 . (pl + pt + lt)
Lp = 2 . (10×5 + 10×6 + 5×6)
Lp = 2 . (50 + 60 + 30)
Lp = 2 . 140
Lp = 280 cm²
..
5³ + 6²
= (5 × 5 × 5) + (6 × 6)
= 125 + 36
= 161
Jawaban:
1.) Lp = 2 × {( pl) + (p × t) + (1 × t)}
= 2 × {(10 cm x 6 cm) + (10 cm x 5 cm) + (6 cm x 5 cm)}
= 2 × (60 cm² + 50 cm² + 30 cm²)
= 2 x 140 cm²
= 280 cm²
2.)5³ + 6²
=125 + 36
=161