Quiz (+50):

Penjelasan dengan langkah-langkah:

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fungsi koooooompossssiiii

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f(x) = 2x + 1

g(x) = x² – 4

h(x) = x – 1

.

= (fOgOh)(0)

= f(g(h(x)))

= f( (x – 1)² – 4)

= f ( (x² – 2x + 1) – 4)

= f ( x² – 2x – 3)

= 2(x² – 2x – 3) + 1

= 2x² – 4x – 6 + 1

= 2(0)² – 4(0) – 5

= –5

i Will surrender

Jawaban:

Diketahui :

f(x) = 2x+1

g(x) = x²-4

h(x) = x-1

Ditanya :

(f.g.h)(0)

Dijawab :

f = (x – 1)² – (2x + 1) – 4 + 1

f = (x² – 2x + 1) – 4 + 1

f = x² – 2x – (4 – 1) + 1

f = (x² – 2x – 3) + 1

= 2 × (x² – 2x – 3) + 1

= 2x² – (2 × 2)x – (3 × 2)x + 1

= 2x² – 4x – 6x + 1

= 2(0)² – 4(0) – 6(0) + 1

= 0 – 0 – 0 + 1

= (– 5)