Quiz (+50): Tentukan perbandingan Luas biru : luas merah (berdasarkan gambar ini)

Misal: HF = n

Luas merah = (1/2) × alas × tinggi

= (1/2) × AB × EF

= (1/2) × 2n × 2n

= 2n²

Luas Biru = Luas DAF + Luas DFH + Luas HFB

= (1/2) × DA × DF + (1/2) × DF × HF + (1/2) × HF × HG

= (1/2) × 2n × n + (1/2) × n × n + (1/2) × n × n

= n² + (1/2) n² + (1/2) n²

= 2n²

Maka:

Luas Biru : Luas Merah = 1 : 1

L merah
= 1/2 x a x t
= 1/2 x AB x EF
= 1/2 x 2 x 2
= 2

L biru
= L.ADHE + L.EBH – L.merah
= (AD + EH) x DF/2 + 1/2 x EB x EH – 2
= (2+3) x 1/2 + 1/2 x 1 x 3 – 2
= 5/2 + 3/2 – 2
= 4-2
=2

maka perbandingan luas merah dan luas biru adalah 1:1