Quiz LawZ45² + 10 =_________________________Maw BA?

By Admin ReiPosted on December 7, 2022

Quiz LawZ45² + 10 =_________________________Maw BA?

$sf Pendahuluan$

Apa itu Eksponen?

$tt Eksponen : atau : Perpangkatan$ adalah Hasil dari perkalian yg berulang ulang dari bilangan tersebut

■Bentuk Umum Eksponen

$sf {a}^{b} = a times a times a times a times ... times a times a = ...$

■Sifat Sifat Eksponen:

$sf {a}^{b} times {a}^{c} = {a}^{(b+c)}$

$sf {a}^{b} div {a}^{c} = {a}^{(b-c)}$

$sf {(a}^{b}{)}^{c} = {a}^{(b times c)}$

$sf {a}^{0} = 1$

$sf ({a}^{m} times {a}^{n}{)}^{b} = {a}^{mb} times {a}^{nb}$

$sf {a}^{m} times {c}^{m} = (a times b{)}^{m}$

■□■□■□■□■□■□■□■

Contoh Eksponen Menyederhanakan:

$tt {123}^{100} times {123}^{123} = {123}^{(100 + 123)} = {123}^{223}$

Contoh Eksponen Berulang Ulang:

■Contoh Eksponen Pangkat 2(1 – 10):

$tt {1}^{2} = 1$

$tt {2}^{2} = 4$

$tt {3}^{2} = 9$

$tt {4}^{2} = 16$

$tt {5}^{2} = 25$

$tt {6}^{2} = 36$

$tt {7}^{2} = 49$

$tt {8}^{2} = 64$

$tt {9}^{2} = 81$

$tt {10}^{2} = 100$

■Contoh Eksponen Pangkat 3(1-10):

$tt {1}^{3} = 1$

$tt {2}^{3} = 8$

$tt {3}^{3} = 27$

$tt {4}^{3} = 64$

$tt {5}^{3} = 125$

$tt {6}^{3} = 216$

$tt {7}^{3} =343$

$tt {8}^{3} =512$

$tt {9}^{3} = 729$

$tt {10}^{3} = 1.000$

■Cara Mengerjakan Pangkat 2(1-10):

$tt {1}^{2} = 1 times 1 = 1$

$tt {2}^{2} = 2 times 2 = 4$

$tt {3}^{2} = 3 times 3 = 9$

$tt {4}^{2} = 4 times 4 = 16$

$tt {5}^{2} = 5 times 5 = 25$

$tt {6}^{2} = 6 times 6 = 36$

$tt {7}^{2} = 7 times 7 = 49$

$tt {8}^{2} = 8 times 8 = 64$

$tt {9}^{2} = 9 times 9 = 81$

$tt {10}^{2} = 10 times 10 = 100$

■Cara mengerjakan Pangkat 3(1-10):

$tt {1}^{3} = 1 times 1 times 1 = 1$

$tt {2}^{3} =2 times 2 times 2 = 8$

$tt {3}^{3} = 3 times 3 times 3 = 27$

$tt {4}^{3} = 4 times 4 times 4 = 64$

$tt {5}^{3} = 5 times 5 times 5 = 125$

$tt {6}^{3} = 6 times 6 times 6 = 216$

$tt {7}^{3} = 7 times 7 times 7 = 343$

$tt {8}^{3} = 8 times 8 times 8 =512$

$tt {9}^{3} = 9 times 9 times 9 =729$

$tt {10}^{3} = 10 times 10 times 10 = 1.000$

$colorbox{lavender}{PENYELESAIAN}$

45² + 10

= (45 × 45) + 10

= 2.025 + 10

=> 2.035

$colorbox{Lavender}{Pelajari Lebih Lanjut}$

Contoh Soal Eksponen: brainly.co.id/tugas/47350497 brainly.co.id/tugas/47313559

brainly.co.id/tugas/47410248

brainly.co.id/tugas/47410243

$tt >> orange{Detail} : green{Jawaban} tt$

• Matpel: Matematika

• Kelas: 5

• Materi: Bab 7

• Kode Soal: 2

• Kata Kunci: Eksponen

$purple{boxed{pink{boxed{orange{tt{star~blue{ Snaly01 }~star}}}}}}$

Jawaban:

45² + 10

= (45 × 45) + 10

= 2.025 + 10

= 2.035