Quiz (Math) [+50]

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Triple Pythagoras
(1) 5, 12, x
(2) 20, 25, x
(3) 12, x, 20
Tentukan nilai x

Quiz (Math) [+50]

Jawaban:

  1. 13
  2. 15
  3. 16

Penjelasan dengan langkah-langkah:

NO. 1

tt5~~~~~12~~~~~ boxed{13}

pembuktian :

 tt {a}^{2} + {b}^{2} = {c}^{2}

tt {5}^{2} + {12}^{2} = {x}^{2}

tt25 + 144 = {x}^{2}

 tt169 = {x}^{2}

 tt sqrt{169} = x

 tt sqrt{ {13}^{2} } = x

tt13 = x \

NO. 2

tt20~~~~~25~~~~~ boxed{15} ~~~~\ tt↓ : 5~~↓ : 5~~↑ times 5 \ tt4~~~~~~~5~~~~~~~~3~~~~~~

pembuktian :

 tt {c}^{2} - {b}^{2} = {a}^{2}

 tt {25}^{2} - {20}^{2} = {x}^{2}

 tt625 - 400 = {x}^{2}

 tt225 = {x}^{2}

 tt sqrt{225} = x

 ttsqrt{ {15}^{2} } = x

NO. 3

tt12~~~~~ boxed{16}~~~~~20 ~~~~~\ tt~↓ : 4~~ ↑ times 4~~ ↓ : 4~ \ tt~3~~~~~~~4~~~~~~~~~5~~~~~

pembuktian :

 tt {c}^{2} - {a}^{2} = {b}^{2}

 tt{20}^{2} - {12}^{2} = {x}^{2}

 tt400 - 144 = {x}^{2}

 tt256 = {x}^{2}

 tt sqrt{256} = x

 tt sqrt{ {16}^{2} } = x

 tt16 = x

(1)

5, 12, x

a² + b² = c²

5² + 12² = x²

x² = 25 + 144

x² = 169

x = 13

(2) 20, 25, x

a² = c² – b²

x² = 25² – 20²

x² = 625 – 400

x² = 225

x = 15

(3) 12, x, 20

b² = c² – a²

x² = 20² – 12²

x² = 400 – 144

x² = 256

x = 16