Req 1 , dari => Ank Tante Anita :vSoal terlampir​

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Ank Tante Anita :vSoal terlampir​”>

Req 1 , dari => Ank Tante Anita :vSoal terlampir​

Detail Jawaban✍

  • Mapel : Matematika
  • Kelas : XI (SMA)
  • Materi : Turunan Fungsi Aljabar
  • Kode Soal : 2
  • Kode Kategorisasi : 11.2.9

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f (x) = x! + x!! – 3x

f (5) = 5! + 5!! – 3 (5)

f (5) = (5 × 4 × 3 × 2 × 1) + (5 × 3 × 1) – 3 × 5

f (5) = (20 × 3 × 2 × 1) + (15 × 1) – 15

f (5) = (60 × 2 × 1) + 15 – 15

f (5) = (120 × 1) + 15 – 15

f (5) = 120 + 15 – 15

f (5) = 135 – 15

f (5) = 120 ✔

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Gambar Jawaban

~Fungsi

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f(x) = x! + x!! – 3x

f(5) = 5! + 5!! – 3(5)

f(5) = ( 5 × 4 × 3 × 2 ) + 5!! – 3(5)

f(5) = ( 20 × 3 × 2 ) + 5!! – 3(5)

f(5) = ( 60 × 2 ) + 5!! – 3(5)

f(5) = 120 + 5!! – 3(5)

f(5) = 120 + ( 5 × 3 × 1 ) – 3(5)

f(5) = 120 + ( 15 × 1 ) – 3(5)

f(5) = 120 + 15 – 3(5)

f(5) = 120 + 15 – 15

f(5) = 120 + 0

f(5) = 120

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DETAIL JAWABAN :

Mapel = Math

Kelas = 8

Bab = 3 – fungsi

Kata Kunci = Operasi hitung pada fungsi

bf : joycha