req soal klo mau._ - Universityku

req soal klo mau._

$displaystyle{sf{int {9x^2} , dx }}$

$displaystyle{sf{frac{9x^{2+1}}{2+1} +~C}}$

$displaystyle{sf{frac{9x^{3}}{3} +~C}}$

3x³ + C

Penjelasan dengan langkah-langkah:

$sf int ({9x}^{2} )dx \$

$sf = frac{9x^2+1}{2 + 1} + c$

$sf = frac{9 {x}^{3} }{2 + 1} + c$

$sf = frac{9 {x}^{3} }{3} + c$

$bf = 3 {x}^{3} + c$