sebanyak 1,492 gram Hg2SO4 larut dalam 1.000cm3 air murni.Ksp HgSO4 sebesar….mol/L (Ar : Hg = 200,6, S = 32, O = 16)

Mr Hg2SO4 = (2×200)+32+(4×16) = 496
1000 cm3 = 1 dm3 = 1 liter

n Hg2SO4 = massa/Mr = 1,492/496 = 0,003

Ksp = n Hg2SO4/volume
= 0,003/1 liter
= 0,003 mol/L