Sec^2A – tan^2A + tanA÷ SecA = SinA+CosA
Jawaban Terkonfirmasi
(sec² A – tan² A + tan A) : sec A = sin A + cos A
[(1 + tan² A)-tan² A+tan A ]: 1/cos A=[1 + tan² A – tan² A + tan A] x cos A
= (1 + tan A) x cos A
= [1 + (sin A/cos A) ] x cos A
= cos A + sin A …. terbukti