sederhanakan?
'6 log 2^3 – '6 log 2 – '6 log 3^2 =
3('6 log 2) – '6 log 2 – 2('6 log 3) =
2('6 log 2) – 2('6 log 3) =
2('6 log 2- '6 log 3)
sederhanakan?
'6 log 2^3 – '6 log 2 – '6 log 3^2 =
3('6 log 2) – '6 log 2 – 2('6 log 3) =
2('6 log 2) – 2('6 log 3) =
2('6 log 2- '6 log 3)