Segitiga ABC degan sin A=4/5 dan sin B=3/5 .jika panjang AC=15 cm tentukan panjang BC

Sin A = 4/5 ⇒ y/r = 4/5 ⇒ BC/AC = 4/5
sin B = 3/5 ⇒ x/r = 3/5 ⇒ AB/AC = 3/5

maka

BC/AC = 4/5
⇒ BC/15 = 4/5
⇒ BC = 4/5 · 15
⇒ BC = 12 cm

Terimakasih semoga membantu

Sin A = 4/5 || sin B=3/5 || AC = 15cm ||

sin B = (AC/BA)
3/5 = 15/BA
BA = 75/3 = 25 cm

sin A = (BC/BA)
4/5 = BC/25
BC = 100/5 = 20cm