selamat mengerjakan

selamat mengerjakan

Jawab:

1.AB -> pythagoras

$20^{2}$ = $12^{2}$ + $b^{2}$

400 = 144 + $b^{2}$

$b^{2}$ = 400 – 144

$b^{2}$ = 256

b = $sqrt{256}$ = 16

2.AD -> pythagoras

$13^{2}$ = $12^{2}$ + $b^{2}$

$b^{2}$ = 169 – 144 = 25

b = $sqrt{25}$ = 5

3.BD = 16 – 5 = 11

Penjelasan dengan langkah-langkah: