SELESAIKAN SETIAP PERSAMAAN EKSPONENSIAL BERIKUT. bantu in kak, jgn sembarangan yaa

Posted on

SELESAIKAN SETIAP PERSAMAAN EKSPONENSIAL BERIKUT. bantu in kak, jgn sembarangan yaa

SELESAIKAN SETIAP PERSAMAAN EKSPONENSIAL BERIKUT. bantu in kak, jgn sembarangan yaa

Sifat Eksponensial yang digunakan:

▪︎a^{m+n} = a^{m} . a^{n}

▪︎a^{m-n} = frac{a^{m}}{a^{n}}

▪︎(a^{m})^{n} = a^{m times n}

Sifat Operasi yang digunakan:

Distributif: (a.b) + (a.c) = a . (b + c)

===============================

a.)

2^{x} + 2^{x+3} = 72

2^{x} + 2^{x} . 2^{3} = 72

2^{x} + 2^{x} . 8 = 72

2^{x} . 1 + 2^{x} . 8 = 72

2^{x} (1 + 8) = 72

2^{x} (9) = 72

2^{x} = 8

2^{x} = 2^{3}

x = 3

b.)

3^{x} + 3^{x+2} = 90

3^{x} + 3^{x} . 3^{2} = 90

3^{x} + 3^{x} . 9 = 90

3^{x} . 1 + 3^{x} . 9 = 90

3^{x} (1 + 9) = 90

3^{x} (10) = 90

3^{x} = 9

3^{x} = 3^{2}

x = 2

c.)

4^{x+1} + 2^{2x} = 20

(2^{2})^{x+1} + 2^{2x} = 20

2^{2(x+1)} + 2^{2x} = 20

2^{2x+2} + 2^{2x} = 20

2^{2x} . 2^{2} + 2^{2x} = 20

2^{2x} . 4 + 2^{2x} = 20

2^{2x} . 4 + 2^{2x} . 1 = 20

2^{2x} (4 + 1) = 20

2^{2x} (5) = 20

2^{2x} = 4

2^{2x} = 2^{2}

2x = 2

x = 1

d.)

2^{x} - 2^{x-2} = -12

2^{x} - frac{2^{x}}{2^{2}} = -12

2^{x} - frac{2^{x}}{4} = -12

Kedua ruas dikalikan 4

2^{x}(4) - 2^{x} = -12(4)

2^{x} . 4 - 2^{x} . 1 = -48

2^{x} (4 - 1) = -48

2^{x} (3) = -48

2^{x} = -16

2^{x} = -2^{4}

Tidak bisa ditentukan hasilnya.

Jika soalnya 2^{x} - 2^{x-2} = 12 ada hasilnya

2^{x} - 2^{x-2} = 12

2^{x} - frac{2^{x}}{2^{2}} = 12

2^{x} - frac{2^{x}}{4} = 12

Kedua ruas dikalikan 4

2^{x}(4) - 2^{x} = 12(4)

2^{x} . 4 - 2^{x} . 1 = 48

2^{x} (4 - 1) = 48

2^{x} (3) = 48

2^{x} = 16

2^{x} = 2^{4}

x = 4

e.)

3^{x^{2}-5} - 9^{x-1} = 0

3^{x^{2}-5} = 9^{x-1}

3^{x^{2}-5} = (3^{2})^{x-1}

3^{x^{2}-5} = 3^{2(x-1)}

3^{x^{2}-5} = 3^{2x-2}

x^{2}-5 = 2x-2

x^{2}-5-2x+2 = 0

x^{2}-2x-3 = 0

(x-3)(x+1) = 0

x-3 = 0

x = 3

atau

x+1 = 0

x = -1

f.)

5^{x^{2}+3} - 25^{2x} = 0

5^{x^{2}+3} = 25^{2x}

5^{x^{2}+3} = (5^{2})^{2x}

5^{x^{2}+3} = 5^{2(2x)}

5^{x^{2}+3} = 5^{4x}

x^{2}+3 = 4x

x^{2}+3-4x = 0

x^{2}-4x+3 = 0

(x-3)(x-1) = 0

x-3 = 0

x = 3

atau

x-1 = 0

x = 1

Semoga Membantu.