selesaikan sistem persamaan linear tiga variabel berikut dengan metode eliminasi beserta caranya! tolong dibantu ya kak​

X+y+z= 2
x+2y+3z = 1
——————— –
-y -z = 1

2x -y -z = 4
x + y + z = 2 (x2)
—————————- –
-3y -3z = 0

-3y -3z =0
-y-2z= 1 (x3)
——————— +
-9z = 3
z =-3

-y -2 z = 1
-y-2(-3) = 1
-y + 6 = 1
y = 6

x+y+z= 2
x+6-3= 2
x = -1