Siapapun yang tau tolong bantu ya

sumbu x

F2x = 10 x cos 53° = 10 x 3/5 = 6 N

F3x = -5 x cos 37° = -5 x 4/5 = -4 N

sigma Fx = 6 +(-4) = 2 N

sumbu Y

F2y = 10 x sin 53 ° = 10 x 4/5 = 8 N

F3y = 5 x sin 37° = 5 x 3/5 = 3 N

sigma Fy = 8 + 3 = 11 N

resultan =

√(2² + 11²) =

√(4+121) =

√125