Simpangan getar gelombang y= 10 sin pi (0.4t – 0.5x).tentukan:

Amplitudo
A = 10m =10cm

periode
T = 1 : f
= 1 : 0,2
=5

frekuensi
2 phi f = 0,4 phi
f = 0.4 : 2 = 0.2 hz

panjang gel
lamda = 2 phi : 0,5
= 2 × 3,14 : 0,5 = 12,56

Cepat rambat prekuensi
v = f × lamda
= 0,2 × 12,56 = 2,512 m/s

Rumus Umum:
y= A sin (wt-kx)
SOAL:
y= 10 sin pi (0.4t-0.5x) = 10 sin (0.4tpi-0.5xpi)
1. A= 10 m
2. Periode/T= 1/f =》f = w/2pi = 0.4pi/2pi = 0.5 (f) T= 1/0.5 = 2 s
3. f = 1/T = 1/2 = 0.5 hz
4. pjg gel=》lamda = 2pi/k = 2pi/0.5pi= 4 m
5. V= lamda.f = 4×0.5= 2 m/s
Silahkan dikoreksi kembali