Sin 150° +cos225°-½ tan (-45°)
Jawaban Terkonfirmasi
Kelas 10 Matematika
Bab Trigonometri
sin 150° + cos 225° – 1/2 . tan (-45°)
= 1/2 + (-1/2 √2) – 1/2 . (-1)
= 1/2 – 1/2 √2 + 1/2
= 1 – 1/2 √2
= (2 - √2)/2
Sin 150° +cos225°-½ tan (-45°)
Kelas 10 Matematika
Bab Trigonometri
sin 150° + cos 225° – 1/2 . tan (-45°)
= 1/2 + (-1/2 √2) – 1/2 . (-1)
= 1/2 – 1/2 √2 + 1/2
= 1 – 1/2 √2
= (2 - √2)/2