Sin 270°.sin 135°.tan225°/sin 150°
.sin225°=
Jawaban Terkonfirmasi
Bab Trigonometri
Matematika SMA Kelas X
(sin 270° . sin 135° . tan 225°) / (sin 150° . sin 225°)
= (-1 . 1/2 √2 . 1) / (1/2 . (-1/2 √2))
= 1 : 1/2
= 1 x 2/1
= 2
Sin 270°.sin 135°.tan225°/sin 150°
.sin225°=
Bab Trigonometri
Matematika SMA Kelas X
(sin 270° . sin 135° . tan 225°) / (sin 150° . sin 225°)
= (-1 . 1/2 √2 . 1) / (1/2 . (-1/2 √2))
= 1 : 1/2
= 1 x 2/1
= 2