(sin 45 × cos 135 + tan² 120) ÷ 2 sin 60 × cos 30
(Sin 45 x cos 135 + tan²120) ÷ 2 sin 60 x cos 30
= (1/2 √2 x – 1/2 √2 + (-√3)²) ÷ 2.1/2 √3 x 1/2 √3
= (-2 + 3) ÷ √3 x 1/2 √3
= 1 ÷ √3 x 1/2 √3
=1/3 √3 x 1/2 √3
= 3/6
=1/2
semoga membantu
(sin 45 × cos 135 + tan² 120) ÷ 2 sin 60 × cos 30
(Sin 45 x cos 135 + tan²120) ÷ 2 sin 60 x cos 30
= (1/2 √2 x – 1/2 √2 + (-√3)²) ÷ 2.1/2 √3 x 1/2 √3
= (-2 + 3) ÷ √3 x 1/2 √3
= 1 ÷ √3 x 1/2 √3
=1/3 √3 x 1/2 √3
= 3/6
=1/2
semoga membantu