Sistem persamaan y=2x+5 dan y=xkuadrat +4x-3 memiliki penyelesaian

Y = y
2x + 5 = x² + 4x – 3
0 = x² + 4x – 3 – 2x – 5
0 = x² + 2x – 8
0 = x² + 4x – 2x – 8
0 = x(x + 4) – 2(x + 4)
0 = (x + 4)(x – 2)
x = -4 atau x = 2

Jika x = -4:
y = 2x + 5
y = 2 × (-4) + 5
y = -8 + 5
y = -3

Jika x = 2:
y = 2x + 5
y = 2 × 2 + 5
y = 4 + 5
y = 9

HP = {(-4,-3),(2,9)}