Soal ada di gambar, minta penjelasan. terimakasih​

cari momen inersia bola pejalnya dulu..

r = 20 cm = 2 x 10^-1 m

kec sudut (w) =

750 rpm = 750 x 2π/60 rad/s = 25 π rad/s

momen inersia ya =

I = 2/5 x m x r² = 2/5 x 0,25 x (2x 10^-1)² = 0,1 x 4 x 10^-2 kg m² = 4 x 10^-3 kg m²

momentum sudut =

L = I x w

L = 4 x 10^-3 x 25 π

L = 100 π x 10^-3

L = 100/1000 π

L = 0,1 π kg m²/s

Penjelasan:

Momentum Sudut

L = Iw

I = momen inersia bola pejal (2/5mr^2)

w = kecepatan sudut (rad/s)

w = 750 rpm

= 750 rotasi/menit × 2pi rad/rotasi × 1 menit/60 sekon

= 750×2pi/60

= 25 pi rad/s

L = 2/5mr^2×w

= 2/5×0,25×(0,2^2)×25pi

= 0,4×0,25×0,04×25pi

= 0,1 pi kg m^2/s