Soal nmr 1(abc) 2(abc) 3(ab)

Nomor 1.
a.)
3k = 3(4)
3k = 12

b.)
-5k = -5(4)
-5k = -20

c.)
2k – 9 = 2(4) – 9
2k – 9 = 8 – 9
2k – 9 = -1

Nomor 2.
a.)
2q – 7 = 2(-5) – 7
2q – 7 = -10 – 7
2q – 7 = -17

b.)
m² – 16 = (-8)² – 16
m² – 16 = 64 – 16
m² – 16 = 48

c.)
4p + 3pq = 4(5) + 3(5)(-4)
4p + 3pq = 20 – 60
4p + 3pq = -40

Nomor 3.
a = -3, b = 1, c = -5

a.)
2ab + 3bc – 4ac = 2(-3)(1) + 3(1)(-5) – 4(-3)(-5)
2ab + 3bc – 4ac = -6 – 15 – 60
2ab + 3bc – 4ac = -81

b.)
– Tidak nampak dengan jelas –
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