Soal2. AF (x) = 4x + 121B = F(x) = x² – 4xc=.flx) = x²= f(x) = 12-3x + 2x²2​

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Soal2. AF (x) = 4x + 121B = F(x) = x² – 4xc=.flx) = x²= f(x) = 12-3x + 2x²2​

Jawaban:

(x) = (5x³)/(2x) – (4x²)/(2x) + 6/(2x)

f(x) = (5/2)x² – 2x + 3x⁻¹

f'(x) = 5x – 2 – 3x⁻²

f'(x) = 5x – 2 – (3/x²)

maaf jika salah

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