Suatu fungsi dirumuskan dengan f(x)=2x+1 dengan daerah asal A={-2,-1,0,1,2,3}

F(x) = 2x+1
f(-2) = 2(-2) + 1
    f = -4 + 1
    f = -3
f(x) = 2x+1
f(-1) = 2(-1)+1
f = -2 + 1
f = -1

f(x) = 2x + 1
f(0) = 2(0) +1
f = 0 + 1
f = 1

f(x) = 2x + 1
f(1) = 2(1) + 1
f = 2 + 1
f = 3

f(x) = 2x + 1
f(2) = 2(2) +1
f = 4 + 1
f = 5

f(x) = 2x + 1
f(3) = 2(3) + 1
f = 6 +1
f = 7