Suatu fungsi ditentukan dengan rumus f(x) =ax+b

jika f(4)=5
f(-2)=-7
tentukan:
a. nilai a dan b
b. Rumus fungsinya

bantuin aku dong kk ,abang……….

Suatu fungsi ditentukan dengan rumus f(x) =ax+b

" Nilai Fungsi "

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f( x ) = ax + b

f( 4 ) = 5

f( – 2 ) = – 7

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f¹ = 5

f² = – 7

x¹ = 4

x² = – 2

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$sf a = frac{ {f}^{1} - {f}^{2} }{ {x}^{1} - {x}^{2} }$

$sf a = frac{5 - ( - 7)}{4 - ( - 2)}$

$sf a = frac{12}{6}$

$huge boxed{ sf a = 2}$

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f( – 2 ) = – 7

f( – 2 ) = 2x + b

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2 (–2) + b = – 7

–4 + b = – 7

b = – 7 – ( – 4 )

b = – 7 + 4

$huge boxed{ sf b = - 3}$

______

Jadi :

a = 2

b = – 3

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$huge boxed{ sf f(x) = 2x - 3}$

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Semoga Membantu

$tt boxed{ boxed{ boxed{ sf Answer : By : Ciyo}}}$

Jawaban:

f(x) = ax+b

f(4) = 4a + b = 5 …1

f(2) = 2a + b = -7 ..2–

2a = 12

a = 6

subtitusi ke 1

f(x) = 4(6) + b = 5

f(x) = 24 + b = 5

f(x) b = 5 – 24

f(x) b = -19

f(x) = 6x – 19

smg membantu