Suatu fungsi f(x) = ax + b, jika f(3) = 8 dan f(-2) = 7. Berapakah nilai a + b​

f(x) = ax + b

f(3) = a.3 + b f(-2) = a (-2) + b

8 = 3a + b…(1) 7 = -2a + b

3a + b = 8 Mencari b

-2a + b = 7 -2a + b = 7

—————- – -2.⅕ + b = 7

5a = 1. -⅖ + b = 7

a = ⅕ b = 7 + ⅖ = 37/5 = 7⅖

a + b = ⅕ + 37/5 = 38/5 = 7⅗