Suatu kerucut dikahui r=7cm,t=24dan 22/7

r = 7 cm

t = 24 cm

a. panjang garis pelukis

s² = r² + t²

s² = 7² + 24²

s² = 49 + 576

s² = 625

s = √625

s = 25 cm

b. Luas selimut kerucut

= π x r x s

= 22/7 x 7 x 25

= 22 x 25

= 550 cm²

c. Luas permukaan kerucut

= π x r x (r + s)

= 22/7 x 7 x (7 + 25)

= 22/7 x 7 x 32

= 22 x 32

= 704 cm²