suatu segita ADC siku-siku sama kaki dengan AD=BC.jika panjang sisi miring AC=8cm.hitungla panjang AD !​

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suatu segita ADC siku-siku sama kaki dengan AD=BC.jika panjang sisi miring AC=8cm.hitungla panjang AD !​

Jawaban:

ac=8cm.

panjang ad adalah 16cm

Jawaban:

ΔADC = Δ siku² sama kaki

AC (sisi miring) = 8 cm

AD = BC

ac = sqrt{ {ad}^{2} + {bc}^{2} } \ ac = sqrt{ {ad}^{2} + {ad}^{2} } \ ac = sqrt{2 {ad}^{2} } \ {ac}^{2} = 2 {ad}^{2} \ {8}^{2} = 2 {ad}^{2} \ 64 = 2 {ad}^{2} \ frac{64}{2} = {ad}^{2} \ 32 = {ad}^{2} \ ad = sqrt{32} \ ad = 4 sqrt{2}

panjang AD = 4√2 cm = 5,66 cm