Sumbu simetri pada fungsi f(x)=(x+6)²-5

F(x) = (x+6)² – 5
f(x) = x² + 12x + 36 -5
f(x) = x² + 12x + 31
a = 1
b= 12
c = 31
Rumus Sumbu Simetri = -b/2a = -12/2.1 = -12/2 = -6