T o l o n g d o n g g ! : )
Jawab:
1. 117°
2. 30 cm²
3. 34 meter
Penjelasan dengan langkah-langkah:
1. Jumlah sudut dalam segitiga selalu berjumlah 180 derajat.
∠MKL + ∠KLM + ∠LMK = 180°
52° + 65° + ∠LMK = 180°
∠LMK = 180° – 52° – 65°
∠LMK = 63°
∠LMK dan ∠LMN saling berpelurus, maka jumla kedua sudut tersebut adalah 180°
∠LMK + ∠LMN = 180°
63° + ∠LMN = 180°
∠LMN = 180° – 63°
∠LMN = 117°
2. Luas yang diarsir = Luas Δ ABE + Luas Δ ABD – 2 × Luas Δ ABC
L = (1/2 x 5 x 12) + (1/2 x 5 x 8) – (2 x 1/2 x 5 x 4)
L = 30 + 20 – 20
L = 30 cm²
3. Panjang diagonal persegi panjang selalu sama.
4x + 10 = 6x – 2
10 + 2 = 6x – 4x
12 = 2x
x = 12/2
x = 6
Maka, panjang diagonal tersebut adalah
4x + 10
= 4 x 6 + 10
= 24 + 10
= 34 meter
(jangan lupa tandai sebagai jawaban terbaik 🙂
1]
< LMN = 180° – (180° – 65° – 52°)
< LMN = 180° – 63
< LMN = 117°
atau
< LMN = 65° + 52°
< LMN = 117°
2]
AB = 5 cm
t1 = 3 × 4 = 12 cm
t2 = 2 × 4 = 8 cm
t3 = 4 cm
L = (1/2 × AB × (t1 + t2)) – (2 × 1/2 × AB × t3)
L = (1/2 × 5 × (12 + 8)) – (2 × 1/2 × 5 × 4)
L = (1/2 × 5 × 20) – (2 × 1/2 × 5 × 4)
L = 50 – 20
L = 30 cm^2
3]
d1 = (4x + 10) m
d2 = (6x – 2) m
d1 = d2
4x + 10 = 6x – 2
6x – 4x = 10 + 2
2x = 12
x = 12/2
x = 6
panjang diagonal taman sebenarnya
= (4x + 10) m
= (4(6) + 10) m
= (24 + 10) m
= 34 m