Tentukan [8x³+6x²]dx

Penyelesaian:

∫ ax^n dx = a/(n + 1) x^(n + 1) + C

∫ (8x^3 + 6x^2) dx

= (8/4) x^4 + (6/3) x^3 + C

= 2x^4 + 2x^3 + C

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu

Kode: 11.2.10

Kata Kunci: integral

• IntegraL

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∫ {8x³ + 6x²} dx = ___ ?

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∫ {8x³ + 6x²} dx = ⁸/₍₃₊₁₎ x⁴ + ⁶/₍₂₊₁₎x³ + C

∫ {8x³ + 6x²} dx = ⁸/₄ x⁴ + ⁶/₃ x³ + C

∫ {8x³ + 6x²} dx = 2x⁴ + 2x³ + C

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