Tentukan akar² pangkat

a.x²-10x=0
b.3x²+21=0
c.8x²-8x=0

tolong bantu jawab

Tentukan akar² pangkat

$a) : {x}^{2} - 10x = 0$

$x(x - 10) = 0$

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${x}^{1} = 10$

${x}^{2} = 0$

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$b) : 3 {x}^{2} + 21 = 0$

$3( {x}^{2} + 7) = 0$

Note : Hasil x berkoma

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