Tentukan diferensial dari soal Y = 4x²+2/2x+1​

~ DiferensiαL

y = (4x² + 2) / (2x + 1)

Misal :

u = 4x² + 2 => u' = 8x

v = 2x + 1 => v' = 2

Maka :

y' = (u'v – uv') / v²

y' = (8x (2x + 1) – (4x² + 2) . 2) / (2x + 1)²

y' = ( 16x² + 8x – 8x² – 4) / (2x + 1)²

y' = (8x² + 8x – 4) / (2x + 1)² ✓

– s e m a n g a T