Tentukan f ( x ) jika diketahui f ^1 ( x ) = 3x^2 – 4x + 4 , untuk x = 3 , fungsi f ( x ) bernilai 15

Penyelesaian:

f'(x) = 3x^2 – 4x + 4

f (x) = ∫ (3x^2 – 4x + 4) dx

= (3/3) x^3 – (4/2) x^2 + 4x + C

= x^3 – 2x^2 + 4x + C

f (3) = 15

x^3 – 2x^2 + 4x + C = 15

27 – 18 + 12 + C = 15

21 + C = 15

C = – 6

maka f (x) = x^3 – 2x^2 + 4x – 6

=====================

Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu

Kode: 11.2.10

Kata Kunci: rumus f (x)