Tentukan f(x) jika diketahui f'(x) =-x^2 +2x -3 dan f (3) =0

F(x) = ∫f '(x) dx = – 1/3 x³ + x² – 3x + c
f(3) = 0
-1/3(3³) + (3)²- 3(3) + c= 0
-9 + 9 – 9 + c=0
c= 9
f(x) = – 1/3 x³ + x² – 3x + 9
atau
f(x) = -1/3( x³ – 3x² + 9x – 27)