Tentukan hasil pengurangan a+2ab-1 dari 5a+ab-1

(5a + ab – 1) – (a + 2ab -1)
= 5a + 1ab – 1 – 1a + 2ab + 1
= 5a – 1a + 1ab + 2ab – 1 + 1
= 4a + 3ab

Semoga membantu… ^_^

A + 2ab – 1 dari 5a + ab – 1
= 5a + ab – 1 – (a + 2ab – 1)
= 5a + ab – 1 – a – 2ab + 1
= 5a – a + ab – 2ab – 1 + 1
= 4a – ab