Tentukan hasil perpangkatan bentuk aljabar berikut.

a. (2a)2
b. (3xy)3
c. (–2ab)4
d. (4a2b2)2
e. –3(x2y)3
f. –(2pq)4
g. ½(2xy)2
h. a(ab2)3

Tentukan hasil perpangkatan bentuk aljabar berikut.

Jawaban Terkonfirmasi

$a. : {(2)}^{2} {(a)}^{2} \ = 4 {a }^{2} \ \ b. {(3)}^{3} {(x)}^{3} {(y)}^{3} \ = 27 {x}^{ 3} {y}^{3} \ \ c.( { - 2)}^{4} {a}^{4} {b}^{4} \ = 16 {a}^{4} {b}^{4} \ \ d. {(4)}^{2} { ({a}^{2}) }^{2} { ({b}^{2}) }^{2} \ = 16 {a}^{4} {4b}^{4} \ \ e. - 3(( { {x}^{2}) }^{3} ({y})^{3} \ = - 3 {x}^{6} - 3 {y}^{3} \ \ f. - (( {2)}^{4} {p}^{4} {q}^{4} ) \ = - 16{p}^{4} {q}^{4} : \ \ g. frac{1}{2}( {2}^{2} {x}^{2} {y}^{2} ) \ = frac{1}{2}({4x}^{2} {y}^{2}) : = 2 frac{1}{2} {x}^{2} frac{1}{2} {y}^{2} \ \ h.a(a {b}^{2} ) ^{3} \ = a( {a}^{3} {b}^{6} ) \ = {a}^{4} a {b}^{6}$
= {a}^{5} {b}^{6}