Tentukan himpunan penyelesaian persamaan nilai mutlak di bawah ini 1.(2x+3) + (x-1) =8

Jawaban:

1. (2× + 3) + (×-1) = 8

2× + 3 + × – 1 = 8

2× + × = 8 -3 + 1

3× = 6

× = 6dibagi 3

× = 2

2. ( 3× – 3) + (× + 5) = 10

3× -3 + × + 5 = 10

3× + × = 10 + 3 -5

4× = 8

× = 8 dibagi 4

× = 2

maaf kalau salah