Tentukan himpunan persamaan berikut dengan menggunakan metode eliminasi

1. 4× – 2 y = -4

× + 2y = 4

__________ +

5 × = 0

× = 0/5

× = 0

× + 2y = 4

0 + 2y = 4

y = 4/2

y = 2

2. 2× + y = 5 ×1

× – 3y = -6 ×2

__________ –

2× + y = 5

2× – 6y = -12

_____________ –

0 + 7y = 17

y = 17/7

y = 2,4

2x + y = 5

2× + 2,4 = 5

2× = 5 – 2,4

2× = 2,6

× = 2,6/2

× = 1,3

Semoga mengerti