Tentukan hp dari pesamaan 2 cos 2x + √3 = 0 dan 0°≤ x ≤ 720°

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Tentukan hp dari pesamaan 2 cos 2x + √3 = 0 dan 0°≤ x ≤ 720°

2cos2x+√3 = 0
cos2x =  frac{-1}{2} sqrt{3}

– 2x = 150°+k.360°
    x = 75°+k.180°
  *k=0
   x = 75°+0.180°
   x = 75°
  *k=1
   x = 75°+1.180°
   x = 255°
  *k=2
   x = 75°+2.180°
   x = 435°
  *k=3
   x = 75°+3.180
   x = 615°

– 2x = -150°+k.360
    x = -75°+k.180
  *k=0
   x = -75°+0.180
   x = -75° (tidak memenuhi)
  *k=1
   x = -75°+1.180°
   x = 105°
  *k=2
   x = -75°+2.180°
   x = 285°
  *k=3
   x = -75°+3.180°
   x = 465°
  *k=4
   x = -75°+4.180°
   x = 645°

HP={75°,105°,255°,285°,435°,465°,615°,645°}

Semoga membantu, jadikan yg terbaik yaa:)