Tentukan hp dari sistem persamaan berikut!

A.
3x+4y=23 ( × 1) 3x + 4y = 23
5x-2y=5 ( x 2) 10x – 4y = 10
~~~~~~~~~~~~~~~~~~~~~~~~ +
13x = 33
x = 33/13

3x+4y=23 ( × 5) 15x + 20y = 115
5x-2y=5 ( x 3) 15x – 6y = 15
~~~~~~~~~~~~~~~~~~~~~~~~ –
26y = 100
y = 100/26
y = 50/13

hp = { 33/13 , 50/13 }

b.
y1 = x² + 4x – 5
y2= 2x² + 6x – 13

y2 = y1

2x² + 6x – 13 = x² + 4x – 5

2x² – x² + 6x – 4x -13 + 5 = 0

x² + 2x – 8 = 0

(x + 4)(x – 2) = 0

x1 = -4

y = (-4)² + 4(-4) – 5
y = 16 – 16 – 5
y = -5

tipot = { -4 , -5 }

x2 = 2

y = 2(2)² + 6(2) – 13
y = 8+12 – 13
y = 7

tipot = { 2 , 7 }

A.
3x+4y=23
x=2y/5 + 1
3( 2y/5 +1) +4y= 23
y= 50/13
x= 2(50/13)+1
x= 33/13

b.
y=2x²+6x-13 persamaan 1
y=x²+4x-5 perasamaan 2

2x²+6x-13=x²+4x-5
x1=2, y1= 7
x2=-4, y2= -5