Tentukan jenis akar-akar persamaan kuadrat x² – 3px – 8 = 0 dengan memperhatikan nilai p!

Jawab:

X² + 3px + p + 2 = 0

x1 + x2 = -b/a

x1 + 6 = -3p/1

x1 + 6 = -3p

x1 = -6 – 3p

x1.x2 = c/a

x1.x2 = (p + 2)/1

6×1 = p + 2

6(-6 -3p) = p + 2

-36 – 18p = p + 2

-18p – p = 36 + 2

-19p = 38

p = 38/-19

p = – 2

maaf klo salah