Tentukan jml deret geometri berikut ini: 16+8+4+2+…….+1/64 Tolong dijawab yaa

A = 16
r = 8/16 = 1/2
Un = ar^(n-1)
1/64 = 16.(1/2)^(n-1)
2^-6 = 2^4.2^(-n+1)
2^-6 = 2^(-n+5)
-6 = -n+5
-6-5 = -n
-11 = -n
n = 11

S11 = a(1-r^n)/(1-r)
S11 = 16(1-(1/2)^11)/(1-1/2)
S11 = 16(1-1/2^11)/(1/2)
S11 = 32(1-1/2^11)