Tentukan kemolalan larutan yang mengandung 18% massa C6H12O6. mr C6H12O6 = 78 bntu kak

Misalkan masa larutan 100%,
massa glukosa = 18 gram,
massa air = 100-18 = 82 gram,
m= gr glukosa/Mr glukosa . 1000/Wp,
m = 18/180 .1000/82,
m = 1,22 molal.