Tentukan nilai abc dari soal di bawah​

Penjelasan dengan langkah-langkah:

a = koefisien ber variabel pangkat 2

b = koefisien ber variabel pangkat 1

c = konstanta

1) -3x² + 4x – 3 = 0

=> a = -3

=> b = 4

=> c = -3

2) 2x (3x – 5) + 6 = 0

= 6x² – 10x + 6 = 0

=> a = 6

=> b = -10

=> c = 6

3) 5x² + 2x = -3x – 6

5x² + 2x + 3x + 6 = 0

5x² + 5x + 6 = 0

=> a = 5

=> b = 5

=> c = 6

4) (2x – 3) (3x + 4) = 0

6x² + 8x – 9x – 12 = 0

6x² – x – 12 = 0

=> a = 6

=> b = -1

=> c = -12

5) (x – 4) (x + 4) = 0

x² + 4x – 4x – 16 = 0

x² – 16 = 0

=> a = 1

=> b = 0

=> c = -16